model 9 average on cricket/exam Practice Questions Answers Test with Solutions & More Shortcuts

Question : 1

A batsman in his 12th innings makes a score of 120, and thereby increases his average by 5. The average score after 12th innings is

a) 55

b) 70

c) 60

d) 65

Answer: (d)

Average runs after 12 innings = x (let)

Average runs after 11 innings = x – 5

According to the question,

12x = (x – 5) × 11 + 120

⇒ 12x – 11x = 120 – 55

⇒ x = 65

Question : 2

Average runs scored by 11 players of a cricket team is 23. If the first player scored 113 runs. Find the average runs of the remaining players.

a) 12 runs

b) 27 runs

c) 8 runs

d) 14 runs

Answer: (d)

Total runs scored by remaining 10 cricketers

= 23 × 11 – 113 = 253 – 113 = 140

∴ Required average = $140/10$ = 14 runs

Question : 3 [SSC CHSL 2011]

The batting average of a cricket player for 64 innings is 62 runs. His highest score exceeds his lowest score by 180 runs. Excluding these two innings, the average of remaining innings becomes 60 runs. His highest score was

a) 209 runs

b) 214 runs

c) 180 runs

d) 212 runs

Answer: (b)

Let the cricketer’s highest score be x runs.

∴ 60 × 62 + x + x – 180 = 64 × 62

⇒ 3720 + 2x – 180 = 3968

⇒ 2x = 428

⇒ x = 214 runs

Question : 4 [SSC CGL Tier-I 2016]

The average of runs of a cricket player of 20 innings was 32. How many runs must he make in his next innings so as to increase his average of runs by 4?

a) 114

b) 76

c) 116

d) 170

Answer: (c)

Total runs scored by the cricketer in 20 innings = 32 × 20 = 640

If the runs scored in 21st innings be x, then

640 + x = 21 × 36

⇒ 640 + x = 756

⇒ x = 756 – 640 = 116

Question : 5 [SSC CAPFs SI & CISF 2013]

The batting average for 30 innings of a cricket player is 40 runs. His highest score exceeds his lowest score by 100 runs. If these two innings are not included, the average of the remaining 28 innings is 38 runs. The lowest score of the player is :

a) 18

b) 12

c) 15

d) 20

Answer: (a)

Lowest score = x

Highest score = x + 100

∴ 28 × 38 + x + x + 100 = 30 × 40

⇒ 1064 + 2x + 100 = 1200

⇒ 2x = 1200 – 1164 = 36

⇒ x = 18

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